One-one linear transformations and kernels

More function review: what does it mean for a function to be one-one (or one-to-one)?

A function f:A → B is one-one if no two elements of its domain A map into the same element of its codomain B.

This function is one-one. No two s map onto the same .

 

This function is not one-one, since two s map onto .

Whether or not a linear transformation is one-one depends on its kernel.

The kernel of a linear transformation T:RnRm is the set of vectors in Rn which transform into the zero vector in Rm.

 

A linear transformation T:RnRm is one-one if and only if its kernel contains only the zero vector.

Proof: If T is one-one, it can't map a non-zero vector into 0, since it already maps 0 into 0. This means that its kernel can contain only 0.

Suppose the kernel contains just the zero vector. To check if T is one-one, check if it can map two different vectors u and v in Rn into the same vector in Rm. If T(u) = T(v), then T(u v) = T(u) – T(v) = 0. This means that the non-zero vector uv is in the kernel of T, which is impossible since we assumed the kernel contained just 0. Then T cannot map different vectors into the same vector, and must be one-one.

 

If the linear transformation T:RnRm is one-one, then m ≥ n.

Proof: Suppose T has standard matrix A. Since T is one-one, its kernel contains only the vector 0. That means that the matrix equation Ax = 0 has only the trivial solution x = 0. The reduced row echelon form of A must then have leading 1's in each of its n columns, and thus must have n non-zero rows. It has m rows in total, so m ≥ n.