r = xi + yj + zk
r0 = x0i + y0j + z0k
d = ai + bj + ck.
Then the equation r = r0 + td becomes
xi + yj + zk = (x0i + y0j + z0k) + t(ai + bj + ck)
i.e. (rearrange and collect components together)
xi + yj + zk = (x0 + at)i + (y0 + bt)j + (z0 + ct)k.
Since equal vectors must have equal components, we have
x = x0 + at
y = y0 + bt
z = z0 + ct.
These equations are called the parametric equations for the line.
Notice that the numbers multiplying the parameter t in the parametric equations are the components of the direction vector, while the numbers that do not multiply t are the coordinates of the initial point. This makes it easy to write down parametric equations for a line through a given point in a given direction - for example, the line through (1, 0 -3) with direction vector [-2, 3, 0] has parametric equations
x = 1 + (-2)t y = 0 + 3t i.e. z = -3 + 0t |
x = 1 - 2t |
Conversely, the line with parametric equations
x = 5t
y = -4
z = 5 + 7t
has an initial point (0, -4, 5) and a direction vector [5, 0, 7].
x = x0 + at
y = y0 + bt.
So, for example, the line through (1, 2) with direction vector [3, 2] has parametric equations
x = 1 + 3t
y = 2 + 2t,
and the line with parametric equations
|
i.e. | x = 3 + 0t y = 2 +(–1)t |
is a vertical line through (3, 2).
Using Vectors to Describe Lines | |||||
Introduction | The vector form of a line | The parametric form of a line | The symmetric form of a line | Finding lines | Uniform linear motion |